Which of following oxides is acidic in nature?

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p-Block Elements - I

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Which of the following oxides is acidic in nature?

$B_2O_3$

$Ga_2O_3$

$Al_2O_3$

$In_2O_3$

Solution

$\mathrm{B}_{2} \mathrm{O}_{3}$ is acidic oxide, $\mathrm{Al}_{2} \mathrm{O}_{3}$ and $\mathrm{Ga}_{2} \mathrm{O}_{3}$ are amphoteric and $\mathrm{In}_{2} \mathrm{O}_{3}$ is basic oxide.

Standard 11

Chemistry

Give origin of group $13$ elements

medium

Boric acid is an acid because its molecule

easy

A metal $(X)$ dissolves both in dil. $HCl$ and dil. $NaOH$ to liberate $H _2$. Addition of $NH _4 Cl$ and excess $NH _4 OH$ to an $HCl$ solution of $X$ produces $Y$ as a precipitate. $Y$ is also produced by adding $NH _4 Cl$ to the $NaOH$ solution of $X$. The species $X$ and $Y$, respectively, are

medium

(KVPY-2015)

Soft heavy metal melts at ${30\,^o}C$ and is used in making heat sensitive thermometers the metal is

medium

Consider the following statements for diborane

$1.$ Boron is approximately $sp^3$ hybridized

$2.$ $B-H-B$ angle is $180^o$

$3.$ There are two terminal $B-H$ bonds for each boron atom

$4.$ There are only $12$ bonding electrons available

Of these statements

normal

Which of the following oxides is acidic in nature?

Solution

Similar Questions

Give origin of group $13$ elements

Boric acid is an acid because its molecule

A metal $(X)$ dissolves both in dil. $HCl$ and dil. $NaOH$ to liberate $H _2$. Addition of $NH _4 Cl$ and excess $NH _4 OH$ to an $HCl$ solution of $X$ produces $Y$ as a precipitate. $Y$ is also produced by adding $NH _4 Cl$ to the $NaOH$ solution of $X$. The species $X$ and $Y$, respectively, are

Soft heavy metal melts at ${30\,^o}C$ and is used in making heat sensitive thermometers the metal is

Consider the following statements for diborane $1.$ Boron is approximately $sp^3$ hybridized $2.$ $B-H-B$ angle is $180^o$ $3.$ There are two terminal $B-H$ bonds for each boron atom $4.$ There are only $12$ bonding electrons available Of these statements

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Consider the following statements for diborane

$1.$ Boron is approximately $sp^3$ hybridized

$2.$ $B-H-B$ angle is $180^o$

$3.$ There are two terminal $B-H$ bonds for each boron atom

$4.$ There are only $12$ bonding electrons available

Of these statements